How to fix The right-hand side of an arithmetic operation must be of type 'any', 'number', 'bigint' or an enum type in TypeScript

// Incorrect - causes TS2363 error
const result = 5 - '3';

// Correct - convert to number first
const result = 5 - Number('3');
const result2 = parseInt('10') + 5;
const result3 = parseFloat('3.14') * 2;

// Incorrect - causes TS2363 error
const diff = new Date() - new Date('2024-01-01');

// Correct - use getTime()
const diff = new Date().getTime() - new Date('2024-01-01').getTime();

// Or use valueOf()
const diff2 = new Date().valueOf() - new Date('2024-01-01').valueOf();

// Incorrect - implicit string type
const value = '42';
const result = 10 + value; // TS2363 error

// Correct - explicitly type as number
const value: number = 42;
const result = 10 + value;

// Or convert at usage
const value = '42';
const result = 10 + Number(value);

// Incorrect - 'value' could be string
const value: number | string = getValue();
const result = value + 5; // TS2363 error

// Correct - type guard or assertion
const value: number | string = getValue();
if (typeof value === 'number') {
  const result = value + 5; // Safe now
}

// Or convert
const result = Number(value) + 5;

// Regular number (safe up to 2^53 - 1)
const smallNum: number = 42;
const result1 = smallNum + 5;

// BigInt for larger numbers
const largeNum: bigint = 9007199254740991n;
const result2 = largeNum + 5n; // Must use bigint literals (n suffix)

// Can't mix number and bigint
const mixed = smallNum + largeNum; // TS2363 error - convert first
const correct = BigInt(smallNum) + largeNum;