How to fix 'super' keyword is unexpected here in TypeScript

// WRONG - using super outside a class
function someFunction() {
  super.someMethod(); // Error: 'super' keyword is unexpected here
}

// CORRECT - using super inside a class method
class ChildClass extends ParentClass {
  someMethod() {
    super.someMethod(); // Valid: inside class method
  }
}

// WRONG - using super in static method
class ChildClass extends ParentClass {
  static staticMethod() {
    super.staticMethod(); // Error: 'super' cannot be referenced in static initializers
  }
}

// CORRECT - calling parent static method directly
class ChildClass extends ParentClass {
  static staticMethod() {
    ParentClass.staticMethod(); // Valid: reference parent class directly
  }
}

class ParentClass {
  parentMethod() {
    return "parent";
  }
}

class ChildClass extends ParentClass {
  // WRONG - arrow function doesn't have super
  childMethod = () => {
    super.parentMethod(); // Error: 'super' keyword is unexpected here
  };

  // CORRECT - use regular method syntax
  childMethod() {
    super.parentMethod(); // Valid
  }

  // ALTERNATIVE - bind arrow function to access parent method
  childMethod = () => {
    ParentClass.prototype.parentMethod.call(this); // Access parent method directly
  };
}

class ParentClass {
  constructor(public name: string) {}
}

class ChildClass extends ParentClass {
  // WRONG - missing super() call
  constructor(name: string, public age: number) {
    this.age = age; // Error: 'super' must be called before accessing 'this'
  }

  // CORRECT - call super() first
  constructor(name: string, public age: number) {
    super(name); // Must be called first
    this.age = age; // Now valid
  }

  // WRONG - super() called after this
  constructor(name: string, public age: number) {
    this.age = age; // Error: 'super' must be called first
    super(name);
  }
}

// WRONG - using super in object literal
const obj = {
  method() {
    super.toString(); // Error: 'super' keyword is unexpected here
  }
};

// CORRECT - use classes instead
class MyClass {
  method() {
    super.toString(); // Valid if MyClass extends something
  }
}

// WRONG - using super as a variable name
const super = "something"; // Error: 'super' is a reserved word

// CORRECT - use different variable name
const parentRef = "something";

// WRONG - trying to access super properties incorrectly
class ChildClass extends ParentClass {
  method() {
    const prop = super; // Error: 'super' can only be used to call methods
    prop.someMethod(); // This won't work
  }
}

// CORRECT - call super methods directly
class ChildClass extends ParentClass {
  method() {
    super.someMethod(); // Valid
  }
}

// WRONG - class doesn't extend anything
class StandaloneClass {
  constructor() {
    super(); // Error: 'super' keyword is unexpected here
  }
}

// CORRECT - only use super when extending
class ChildClass extends ParentClass {
  constructor() {
    super(); // Valid
  }
}

// Check your imports and class definitions
import { ParentClass } from "./ParentClass";

// Ensure the parent class is properly defined
class ParentClass {
  // ... implementation
}

class ChildClass extends ParentClass {
  // Now super will work
  constructor() {
    super();
  }
}

class ParentClass {
  logMessage(message: string) {
    console.log("Parent: " + message);
  }
}

class ChildClass extends ParentClass {
  // CORRECT - override and call parent method
  logMessage(message: string) {
    super.logMessage(message); // Call parent implementation
    console.log("Child: " + message); // Add child behavior
  }

  // WRONG - incorrect super usage in non-override
  someNewMethod() {
    super.nonExistentMethod(); // Error if parent doesn't have this method
  }

  // CORRECT - check if method exists
  someNewMethod() {
    if (super.logMessage) {
      super.logMessage("calling from new method");
    }
  }
}